Q1Single correct4 Marks10 May 2026

Consider the two quadratic functions $y_1 = x^2 - 4x + 1$ and $y_2 = x^2 - 6x - 3$. A quadratic function $f(x) = ax^2 + bx + c$ has its vertex at the intersection point of the graphs of $y_1$ and $y_2$, its $y$-intercept is $2$, and its axis of symmetry is parallel to the $y$-axis. What is the equation of $f(x)$?

A

$y = -\frac{11}{4}(x + 2)^2 + 13$

B

$y = -\frac{11}{4}(x - 2)^2 + 13$

C

$y = \frac{11}{4}(x + 2)^2 + 13$

D

$y = -\frac{11}{4}(x + 2)^2 - 13$