Q3Numerical2 Marks21 Dec 2025Find limn→∞an\lim_{n \to \infty} a_nlimn→∞an for the sequence {an}\{a_n\}{an} such that an=n5−3n3+sin(n)2n5+ln(n)+n2a_n = \frac{n^5 - 3n^3 + \sin(n)}{2n^5 + \ln(n) + n^2}an=2n5+ln(n)+n2n5−3n3+sin(n).Your answerPress Enter to check.
