Q12Single correct3 Marks1 Sep 2024Choose the correct option(s).Alimx→0+[xsin(1/x)]=0\lim_{x \to 0^+} [x \sin(1/x)] = 0limx→0+[xsin(1/x)]=0Blimx→∞[e1/xe1/x+1]=0\lim_{x \to \infty} \left[\frac{e^{1/x}}{e^{1/x} + 1}\right] = 0limx→∞[e1/x+1e1/x]=0Climx→0−[xsin(1/x)]=1\lim_{x \to 0^-} [x \sin(1/x)] = 1limx→0−[xsin(1/x)]=1Dlimx→−∞[e1/xe1/x+1]=1\lim_{x \to -\infty} \left[\frac{e^{1/x}}{e^{1/x} + 1}\right] = 1limx→−∞[e1/x+1e1/x]=1
