Q15Comprehension3 Marks28 Apr 2024PassageSuppose X∼Poisson(λ)X \sim \operatorname{Poisson}(\lambda)X∼Poisson(λ) with parameter λ>0\lambda > 0λ>0. Based on the above data, answer the given subquestions.Find the value of lambda for which 3P(X = 3) = 2P(X = 2) + 4P(X = 1).A222B444C111D−2-2−2
