Q5Multiple correct2 Marks31 Aug 2025Let X follow an exponential distribution with parameter λ\lambdaλ . Choose the correct statement(s).AP(X≤2)=e−2P(X \le 2) = e^-2P(X≤2)=e−2BVar(X)=1/λ2\operatorname{Var}(X) = 1 / \lambda ^2Var(X)=1/λ2CThemeanoftheexponentialisthereciprocalofitsparameterλ.The mean of the exponential is the reciprocal of its parameter \lambda .Themeanoftheexponentialisthereciprocalofitsparameterλ.DCDFisgivenasF(x)=e−λxCDF is given as F(x) = e^{-\lambda x}CDFisgivenasF(x)=e−λx
