Q2Comprehension2 Marks10 May 2026PassageSuppose X∼Poisson(λ)X \sim Poisson(\lambda)X∼Poisson(λ). Based on the above data, answer the given subquestions.Find the value of λ\lambdaλ for which 4P(X=2)=5P(X=1)4 P(X = 2) = 5 P(X = 1)4P(X=2)=5P(X=1). Enter the answer correct to one decimal place.Your answerPress Enter to check.
