Q6Comprehension3 Marks28 Apr 2024PassageBased on the given data, answer the following subquestions: Suppose a random variable XXX follows an exponential distribution with mean 5.If P(X≤k)=0.95P(X \le k) = 0.95P(X≤k)=0.95, then find the value of kkk.A15(ln20)\frac{1}{5}(\ln 20)51(ln20)B5(ln20)5(\ln 20)5(ln20)C15(ln2)\frac{1}{5}(\ln 2)51(ln2)D5(ln2)5(\ln 2)5(ln2)
