Q28Multiple correct5 Marks5 Jun 2022Consider a polynomial function p(x)=−0.01(x−1)(x−2)2(x−3)2(x−4)x(x+1)(x+2)2p(x)=-0.01(x-1)(x-2)^2(x-3)^2(x-4)x(x+1)(x+2)^2p(x)=−0.01(x−1)(x−2)2(x−3)2(x−4)x(x+1)(x+2)2. Choose the correct options from the following.Ap(x)p(x)p(x) is one-one function when x∈(−∞,−2)∪(4,∞)x\in(-\infty,-2)\cup(4,\infty)x∈(−∞,−2)∪(4,∞).BThe total number of turning points of p(x)p(x)p(x) is 999.Cp(x)>0p(x)>0p(x)>0 when x∈(−1,0)∪(1,2)∪(2,3)∪(3,4)x\in(-1,0)\cup(1,2)\cup(2,3)\cup(3,4)x∈(−1,0)∪(1,2)∪(2,3)∪(3,4).DThere are exactly 999 points on p(x)p(x)p(x) where the slope of the tangent is zero.
