Q47Numerical2 Marks5 Jun 2022If [a+43b8−6]=[2a+2b+28a−8b]\begin{bmatrix}a+4&3b\\8&-6\end{bmatrix}=\begin{bmatrix}2a+2&b+2\\8&a-8b\end{bmatrix}[a+483b−6]=[2a+28b+2a−8b], then find the value of a+2ba+2ba+2b.Your answerPress Enter to check.