Q5Numerical3 Marks26 Oct 2025Find the minimum value of β\betaβ such that the matrix [β−10−12β+42β+1β+1β+1]\begin{bmatrix}\beta-1&0&-1\\2&\beta+4&2\\\beta+1&\beta+1&\beta+1\end{bmatrix}β−12β+10β+4β+1−12β+1 is not invertible.Your answerPress Enter to check.
