Q19Comprehension1.5 Marks27 Oct 2024PassageLet A=[−2αβ2]A=\begin{bmatrix}-2&\alpha\\\beta&2\end{bmatrix}A=[−2βα2] such that AAT=[8888]AA^T=\begin{bmatrix}8&8\\8&8\end{bmatrix}AAT=[8888]. Based on the above data, answer the given subquestions.Find the value of α\alphaα.Your answerPress Enter to check.
