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Question 23 - Week 2 Practice | Prasnya
Q23
00:00
16 Oct 2022
Q23.
Suppose at
t
=
2
t=2
t
=
2
the distribution vector is
X
2
=
[
1
3
1
2
2
3
]
T
X_2=\begin{bmatrix}\frac13&\frac12&\frac23\end{bmatrix}^T
X
2
=
[
3
1
2
1
3
2
]
T
. Which of the following options are true?
@passage
A
X
0
=
X
2
X_0=X_2
X
0
=
X
2
.
B
X
0
=
X
1
X_0=X_1
X
0
=
X
1
.
C
X
0
≠
X
n
X_0\ne X_n
X
0
=
X
n
for some
n
∈
N
n\in\mathbb{N}
n
∈
N
.
D
There are infinitely many vectors which are possible candidates for
X
0
X_0
X
0
.
E
There are infinitely many vectors which are possible candidates for
X
1
X_1
X
1
.
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Q23
00:00
16 Oct 2022
Q23.
Suppose at
t
=
2
t=2
t
=
2
the distribution vector is
X
2
=
[
1
3
1
2
2
3
]
T
X_2=\begin{bmatrix}\frac13&\frac12&\frac23\end{bmatrix}^T
X
2
=
[
3
1
2
1
3
2
]
T
. Which of the following options are true?
@passage
A
X
0
=
X
2
X_0=X_2
X
0
=
X
2
.
B
X
0
=
X
1
X_0=X_1
X
0
=
X
1
.
C
X
0
≠
X
n
X_0\ne X_n
X
0
=
X
n
for some
n
∈
N
n\in\mathbb{N}
n
∈
N
.
D
There are infinitely many vectors which are possible candidates for
X
0
X_0
X
0
.
E
There are infinitely many vectors which are possible candidates for
X
1
X_1
X
1
.
Save
Read
Check
Details
