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Question 24 - Week 2 Practice | Prasnya
Q24
00:00
16 Oct 2022
Q24.
Suppose at
t
=
1
t=1
t
=
1
the distribution vector is
X
1
=
[
1
2
1
2
0
]
T
X_1=\begin{bmatrix}\frac12&\frac12&0\end{bmatrix}^T
X
1
=
[
2
1
2
1
0
]
T
. Which of the following options is true?
@passage
A
The system had positive initial probabilities of being in State
1
1
1
or State
2
2
2
.
B
The system was initially in State
3
3
3
.
C
The system was initially in State
1
1
1
.
D
The system had positive initial probabilities of being in State
2
2
2
and State
3
3
3
.
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Details
Q24
00:00
16 Oct 2022
Q24.
Suppose at
t
=
1
t=1
t
=
1
the distribution vector is
X
1
=
[
1
2
1
2
0
]
T
X_1=\begin{bmatrix}\frac12&\frac12&0\end{bmatrix}^T
X
1
=
[
2
1
2
1
0
]
T
. Which of the following options is true?
@passage
A
The system had positive initial probabilities of being in State
1
1
1
or State
2
2
2
.
B
The system was initially in State
3
3
3
.
C
The system was initially in State
1
1
1
.
D
The system had positive initial probabilities of being in State
2
2
2
and State
3
3
3
.
Save
Read
Check
Details
