Question 1 - Measures of Central Tendency — effect of linear transformation on mean Practice

Question 1

00:00Est. 1 min

Marks:+4.000.00

Passage

The mean and population standard deviation of marks (out of

50

) scored by the students of class X in an aptitude test are

30

and

5

respectively. If the marks of students are modified as follows: Modified marks

=\frac{2\times \text{Marks}+5}{5}

. Then, based on the given information, answer the subquestions.

Question

What is the mean of the modified marks of students?

Comprehension

Easy Difficulty

05 June 2022

Your answer