Q29Numerical3 Marks29 Oct 2023Suppose X∼Bernoulli(13)X\sim\operatorname{Bernoulli}(\frac{1}{3})X∼Bernoulli(31), Y∼Bernoulli(12)Y\sim\operatorname{Bernoulli}(\frac{1}{2})Y∼Bernoulli(21), and Z∼Bernoulli(23)Z\sim\operatorname{Bernoulli}(\frac{2}{3})Z∼Bernoulli(32) such that fXYZ(0,0,1)=14f_{XYZ}(0,0,1)=\frac{1}{4}fXYZ(0,0,1)=41 and fZ∣Y=1(0)=13f_{Z|Y=1}(0)=\frac{1}{3}fZ∣Y=1(0)=31. Find the value of fX∣Y=0,Z=1(0)f_{X|Y=0,Z=1}(0)fX∣Y=0,Z=1(0). Enter the answer correct to two decimal places.Your answerPress Enter to check.