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Question 39 - Week 2 Practice | Prasnya
Q39
00:00
16 Oct 2022
Q39.
Compute the CDF of
X
X
X
,
F
X
(
k
)
F_X(k)
F
X
(
k
)
, where
k
∈
{
1
,
2
,
…
,
6
}
k\in\{1,2,\ldots,6\}
k
∈
{
1
,
2
,
…
,
6
}
.
@passage
A
F
X
(
k
)
=
k
6
F_X(k)=\frac{k}{6}
F
X
(
k
)
=
6
k
B
F
X
(
k
)
=
(
1
6
)
3
F_X(k)=\left(\frac{1}{6}\right)^3
F
X
(
k
)
=
(
6
1
)
3
C
F
X
(
k
)
=
(
k
+
1
6
)
3
F_X(k)=\left(\frac{k+1}{6}\right)^3
F
X
(
k
)
=
(
6
k
+
1
)
3
D
F
X
(
k
)
=
(
k
6
)
3
F_X(k)=\left(\frac{k}{6}\right)^3
F
X
(
k
)
=
(
6
k
)
3
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Details
Q39
00:00
16 Oct 2022
Q39.
Compute the CDF of
X
X
X
,
F
X
(
k
)
F_X(k)
F
X
(
k
)
, where
k
∈
{
1
,
2
,
…
,
6
}
k\in\{1,2,\ldots,6\}
k
∈
{
1
,
2
,
…
,
6
}
.
@passage
A
F
X
(
k
)
=
k
6
F_X(k)=\frac{k}{6}
F
X
(
k
)
=
6
k
B
F
X
(
k
)
=
(
1
6
)
3
F_X(k)=\left(\frac{1}{6}\right)^3
F
X
(
k
)
=
(
6
1
)
3
C
F
X
(
k
)
=
(
k
+
1
6
)
3
F_X(k)=\left(\frac{k+1}{6}\right)^3
F
X
(
k
)
=
(
6
k
+
1
)
3
D
F
X
(
k
)
=
(
k
6
)
3
F_X(k)=\left(\frac{k}{6}\right)^3
F
X
(
k
)
=
(
6
k
)
3
Save
Read
Check
Details
