Q20Single correct3 Marks25 Feb 2024The CDF of a random variable XXX is given as FX(x)=1−e−4xF_X(x)=1-e^{-4x}FX(x)=1−e−4x for x≥0x\ge0x≥0, and 000 otherwise. What is the value of P(−4<X≤6)P(-4<X\le6)P(−4<X≤6)?Ae−20−e−24e^{-20}-e^{-24}e−20−e−24B1−e−241-e^{-24}1−e−24Ce−24−e−20e^{-24}-e^{-20}e−24−e−20De−24e^{-24}e−24
