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Question 5 - Week 5 Practice | Prasnya
Q5
00:00
16 Mar 2025
Q5.
Choose the set of correct options.
A
The function
f
:
R
→
R
f:\mathbb{R}\to\mathbb{R}
f
:
R
→
R
such that
f
(
x
)
=
−
x
2
+
x
2
f(x)=-x^2+\sqrt{x^2}
f
(
x
)
=
−
x
2
+
x
2
is onto.
B
The function
f
(
x
)
=
x
2
−
5
x
+
6
f(x)=x^2-5x+6
f
(
x
)
=
x
2
−
5
x
+
6
is a one-one function.
C
The function
f
(
x
)
=
e
x
+
5
f(x)=e^{x+5}
f
(
x
)
=
e
x
+
5
is one-one.
D
If
f
f
f
is an invertible function, then
f
−
1
f^{-1}
f
−
1
is a one-one function.
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Q5
00:00
16 Mar 2025
Q5.
Choose the set of correct options.
A
The function
f
:
R
→
R
f:\mathbb{R}\to\mathbb{R}
f
:
R
→
R
such that
f
(
x
)
=
−
x
2
+
x
2
f(x)=-x^2+\sqrt{x^2}
f
(
x
)
=
−
x
2
+
x
2
is onto.
B
The function
f
(
x
)
=
x
2
−
5
x
+
6
f(x)=x^2-5x+6
f
(
x
)
=
x
2
−
5
x
+
6
is a one-one function.
C
The function
f
(
x
)
=
e
x
+
5
f(x)=e^{x+5}
f
(
x
)
=
e
x
+
5
is one-one.
D
If
f
f
f
is an invertible function, then
f
−
1
f^{-1}
f
−
1
is a one-one function.
Save
Check
Details
