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Question 13 - Week 5 Practice | Prasnya
Q13
00:00
1 Dec 2024
Q13.
If
f
(
x
)
=
x
2
f(x)=x^2
f
(
x
)
=
x
2
and
h
(
x
)
=
x
−
1
h(x)=x-1
h
(
x
)
=
x
−
1
, then which of the following option is/are correct?
A
f
∘
h
f\circ h
f
∘
h
is a one-one function.
B
f
(
f
(
h
(
x
)
)
)
×
h
(
x
)
=
(
x
−
1
)
5
f(f(h(x)))\times h(x)=(x-1)^5
f
(
f
(
h
(
x
)))
×
h
(
x
)
=
(
x
−
1
)
5
.
C
There are three distinct solutions for
h
(
h
(
f
(
x
)
)
)
=
0
h(h(f(x)))=0
h
(
h
(
f
(
x
)))
=
0
.
D
h
∘
f
h\circ f
h
∘
f
is a one-one function.
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Check
Details
Q13
00:00
1 Dec 2024
Q13.
If
f
(
x
)
=
x
2
f(x)=x^2
f
(
x
)
=
x
2
and
h
(
x
)
=
x
−
1
h(x)=x-1
h
(
x
)
=
x
−
1
, then which of the following option is/are correct?
A
f
∘
h
f\circ h
f
∘
h
is a one-one function.
B
f
(
f
(
h
(
x
)
)
)
×
h
(
x
)
=
(
x
−
1
)
5
f(f(h(x)))\times h(x)=(x-1)^5
f
(
f
(
h
(
x
)))
×
h
(
x
)
=
(
x
−
1
)
5
.
C
There are three distinct solutions for
h
(
h
(
f
(
x
)
)
)
=
0
h(h(f(x)))=0
h
(
h
(
f
(
x
)))
=
0
.
D
h
∘
f
h\circ f
h
∘
f
is a one-one function.
Save
Check
Details
