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Question 15 - Week 6 Practice | Prasnya
Q15
00:00
6 Aug 2023
Q15.
If
n
n
n
is the number of solutions of the equation
2
2
x
−
5
−
6
⋅
2
x
+
1
=
0
2^{2x-5}-6\cdot2^x+1=0
2
2
x
−
5
−
6
⋅
2
x
+
1
=
0
, then find the value of
4
n
4n
4
n
.
Your Answer
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Q15
00:00
6 Aug 2023
Q15.
If
n
n
n
is the number of solutions of the equation
2
2
x
−
5
−
6
⋅
2
x
+
1
=
0
2^{2x-5}-6\cdot2^x+1=0
2
2
x
−
5
−
6
⋅
2
x
+
1
=
0
, then find the value of
4
n
4n
4
n
.
Your Answer
Save
Check
Details
