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Question 17 - Week 7 Practice | Prasnya
Q17
00:00
4 Aug 2024
Q17.
Find the limit of the sequence
{
a
n
}
\{a_n\}
{
a
n
}
such that
a
n
=
6
+
6
⋅
2
2
+
6
⋅
3
2
+
⋯
+
6
⋅
n
2
4
n
6
+
5
a_n=\frac{6+6\cdot2^2+6\cdot3^2+\cdots+6\cdot n^2}{\sqrt{4n^6+5}}
a
n
=
4
n
6
+
5
6
+
6
⋅
2
2
+
6
⋅
3
2
+
⋯
+
6
⋅
n
2
.
@passage
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Q17
00:00
4 Aug 2024
Q17.
Find the limit of the sequence
{
a
n
}
\{a_n\}
{
a
n
}
such that
a
n
=
6
+
6
⋅
2
2
+
6
⋅
3
2
+
⋯
+
6
⋅
n
2
4
n
6
+
5
a_n=\frac{6+6\cdot2^2+6\cdot3^2+\cdots+6\cdot n^2}{\sqrt{4n^6+5}}
a
n
=
4
n
6
+
5
6
+
6
⋅
2
2
+
6
⋅
3
2
+
⋯
+
6
⋅
n
2
.
@passage
Your Answer
Save
Read
Check
Details
