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Question 18 - Week 7 Practice | Prasnya
Q18
00:00
4 Aug 2024
Q18.
Find the limit of the sequence
{
a
n
}
\{a_n\}
{
a
n
}
such that
a
n
=
100
n
2
−
11
100
n
3
+
7
a_n=\frac{100n^2-11}{100n^3+7}
a
n
=
100
n
3
+
7
100
n
2
−
11
.
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Q18
00:00
4 Aug 2024
Q18.
Find the limit of the sequence
{
a
n
}
\{a_n\}
{
a
n
}
such that
a
n
=
100
n
2
−
11
100
n
3
+
7
a_n=\frac{100n^2-11}{100n^3+7}
a
n
=
100
n
3
+
7
100
n
2
−
11
.
@passage
Your Answer
Save
Read
Check
Details
