Q20Numerical4 Marks24 Mar 2024Consider the function f(x)={3x(x+2)2,x≤−1,2x−3,−1<x≤1,−8x+1,x>1.f(x)=\begin{cases}\frac{3x}{(x+2)^2}, & x\le -1,\\ 2x-3, & -1<x\le 1,\\ -\frac{8}{x+1}, & x>1.\end{cases}f(x)=⎩⎨⎧(x+2)23x,2x−3,−x+18,x≤−1,−1<x≤1,x>1. Find the total number of points in (−2,2](-2,2](−2,2] at which f(x)f(x)f(x) is not continuous.Your answerPress Enter to check.
