Q21Comprehension4 Marks24 Mar 2024PassageFind the limits of the given sequences in the subquestions.{an}\{a_n\}{an} is such that an=100n2−11100n3+7a_n=\frac{100n^2-11}{100n^3+7}an=100n3+7100n2−11. Find limn→∞an\lim_{n\to\infty} a_nlimn→∞an.Your answerPress Enter to check.
