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Question 21 - Week 7 Practice | Prasnya
Q21
00:00
24 Mar 2024
Q21.
{
a
n
}
\{a_n\}
{
a
n
}
is such that
a
n
=
100
n
2
−
11
100
n
3
+
7
a_n=\frac{100n^2-11}{100n^3+7}
a
n
=
100
n
3
+
7
100
n
2
−
11
. Find
lim
n
→
∞
a
n
\lim_{n\to\infty} a_n
lim
n
→
∞
a
n
.
@passage
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Q21
00:00
24 Mar 2024
Q21.
{
a
n
}
\{a_n\}
{
a
n
}
is such that
a
n
=
100
n
2
−
11
100
n
3
+
7
a_n=\frac{100n^2-11}{100n^3+7}
a
n
=
100
n
3
+
7
100
n
2
−
11
. Find
lim
n
→
∞
a
n
\lim_{n\to\infty} a_n
lim
n
→
∞
a
n
.
@passage
Your Answer
Save
Read
Check
Details
