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Question 24 - Week 7 Practice | Prasnya
Q24
00:00
3 Dec 2023
Q24.
Find the limit of the sequence
{
a
n
}
\{a_n\}
{
a
n
}
such that
a
n
=
n
3
+
2
n
2
−
1
n
3
+
3
n
+
1
a_n=\frac{n^3+2n^2-1}{n^3+3n+1}
a
n
=
n
3
+
3
n
+
1
n
3
+
2
n
2
−
1
.
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Q24
00:00
3 Dec 2023
Q24.
Find the limit of the sequence
{
a
n
}
\{a_n\}
{
a
n
}
such that
a
n
=
n
3
+
2
n
2
−
1
n
3
+
3
n
+
1
a_n=\frac{n^3+2n^2-1}{n^3+3n+1}
a
n
=
n
3
+
3
n
+
1
n
3
+
2
n
2
−
1
.
@passage
Your Answer
Save
Read
Check
Details
