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Question 25 - Week 7 Practice | Prasnya
Q25
00:00
3 Dec 2023
Q25.
Find the limit of the sequence
{
a
n
}
\{a_n\}
{
a
n
}
such that
a
n
=
n
3
+
2
n
3
n
+
7
n
a_n=\frac{n^3+2^n}{3^n+7^n}
a
n
=
3
n
+
7
n
n
3
+
2
n
.
@passage
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Q25
00:00
3 Dec 2023
Q25.
Find the limit of the sequence
{
a
n
}
\{a_n\}
{
a
n
}
such that
a
n
=
n
3
+
2
n
3
n
+
7
n
a_n=\frac{n^3+2^n}{3^n+7^n}
a
n
=
3
n
+
7
n
n
3
+
2
n
.
@passage
Your Answer
Save
Read
Check
Details
