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Question 34 - Week 7 Practice | Prasnya
Q34
00:00
2 Apr 2023
Q34.
Find the limit of the sequence
{
a
n
}
\{a_n\}
{
a
n
}
such that
a
n
=
8
n
2
+
10
n
2
n
2
+
6
n
−
7
a_n=\frac{8n^2+10n}{2n^2+6n-7}
a
n
=
2
n
2
+
6
n
−
7
8
n
2
+
10
n
.
@passage
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Q34
00:00
2 Apr 2023
Q34.
Find the limit of the sequence
{
a
n
}
\{a_n\}
{
a
n
}
such that
a
n
=
8
n
2
+
10
n
2
n
2
+
6
n
−
7
a_n=\frac{8n^2+10n}{2n^2+6n-7}
a
n
=
2
n
2
+
6
n
−
7
8
n
2
+
10
n
.
@passage
Your Answer
Save
Read
Check
Details
