Q40Multiple correct5 Marks20 Nov 2022Consider a function fff defined as f(x)={1e1/x+1,x≠00,x=0.f(x)=\begin{cases}\frac{1}{e^{1/x}+1},&x\ne0\\0,&x=0.\end{cases}f(x)={e1/x+11,0,x=0x=0. Which of the following option(s) is/are true?Afff is an unbounded function on R\mathbb{R}R.Blimx→0−f(x)≠limx→0+f(x)\lim_{x\to0^-}f(x)\ne\lim_{x\to0^+}f(x)limx→0−f(x)=limx→0+f(x).Climx→7−f(x)=limx→7+f(x)\lim_{x\to7^-}f(x)=\lim_{x\to7^+}f(x)limx→7−f(x)=limx→7+f(x).Dfff is continuous at x=0x=0x=0.Efff is continuous at x=7x=7x=7.