Q4Single correct4 Marks16 Mar 2025f(x)=asin∣x∣+be∣x∣f(x)=a\sin|x|+be^{|x|}f(x)=asin∣x∣+be∣x∣ is differentiable at x=0x=0x=0, if and only ifAa−b=0a-b=0a−b=0Ba=0a=0a=0Ca+b=0a+b=0a+b=0Db=0b=0b=0
