Q15Comprehension2 Marks4 Aug 2024PassageAnswer the given subquestions.Calculate the limit of the following function at x=1x=1x=1: f(x)=x4−3x3+2x4−5x3+3x2+1f(x)=\frac{x^4-3x^3+2}{x^4-5x^3+3x^2+1}f(x)=x4−5x3+3x2+1x4−3x3+2, if x≠1x\ne1x=1.Your answerPress Enter to check.
