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Question 4 - Week 6 Practice | Prasnya
Q4
00:00
6 Apr 2026
Q4.
Let
v
=
(
a
,
b
,
c
)
∈
R
3
v=(a,b,c)\in\mathbb{R}^3
v
=
(
a
,
b
,
c
)
∈
R
3
be a vector in the kernel of
T
T
T
such that
a
+
b
+
c
=
1
a+b+c=1
a
+
b
+
c
=
1
. Find the value of
a
+
2
b
+
3
c
a+2b+3c
a
+
2
b
+
3
c
up to two decimal places.
@passage
Your Answer
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Q4
00:00
6 Apr 2026
Q4.
Let
v
=
(
a
,
b
,
c
)
∈
R
3
v=(a,b,c)\in\mathbb{R}^3
v
=
(
a
,
b
,
c
)
∈
R
3
be a vector in the kernel of
T
T
T
such that
a
+
b
+
c
=
1
a+b+c=1
a
+
b
+
c
=
1
. Find the value of
a
+
2
b
+
3
c
a+2b+3c
a
+
2
b
+
3
c
up to two decimal places.
@passage
Your Answer
Save
Read
Check
Details
