Q7Single correct2 Marks16 Mar 2025Let A=[2767373727−6767−3727].A=\begin{bmatrix}\frac{2}{7}&\frac{6}{7}&\frac{3}{7}\\\frac{3}{7}&\frac{2}{7}&-\frac{6}{7}\\\frac{6}{7}&-\frac{3}{7}&\frac{2}{7}\end{bmatrix}.A=7273767672−7373−7672. Choose the correct option for A−1A^{-1}A−1.AA−1=[2767373727−6767−3727]A^{-1}=\begin{bmatrix}\frac{2}{7}&\frac{6}{7}&\frac{3}{7}\\\frac{3}{7}&\frac{2}{7}&-\frac{6}{7}\\\frac{6}{7}&-\frac{3}{7}&\frac{2}{7}\end{bmatrix}A−1=7273767672−7373−7672BA−1=[4737272747−4737−2747]A^{-1}=\begin{bmatrix}\frac{4}{7}&\frac{3}{7}&\frac{2}{7}\\\frac{2}{7}&\frac{4}{7}&-\frac{4}{7}\\\frac{3}{7}&-\frac{2}{7}&\frac{4}{7}\end{bmatrix}A−1=7472737374−7272−7474CA−1=[2737676727−3737−6727]A^{-1}=\begin{bmatrix}\frac{2}{7}&\frac{3}{7}&\frac{6}{7}\\\frac{6}{7}&\frac{2}{7}&-\frac{3}{7}\\\frac{3}{7}&-\frac{6}{7}&\frac{2}{7}\end{bmatrix}A−1=7276737372−7676−7372DA−1=[23662−33−62]A^{-1}=\begin{bmatrix}2&3&6\\6&2&-3\\3&-6&2\end{bmatrix}A−1=26332−66−32
