Q9Numerical3 Marks6 Aug 2023Let X,Y,Z∼i.i.d. Geometric(1/2)X, Y, Z \sim \text{i.i.d. Geometric}(1/2)X,Y,Z∼i.i.d. Geometric(1/2). Define a new random variable U=min(X,Y,Z)U = \min(X, Y, Z)U=min(X,Y,Z). What is the value of 1/P(U≥3)1/P(U \ge 3)1/P(U≥3)?Your answerPress Enter to check.
