Q13Numerical3 Marks4 Aug 2024Consider a random variable XXX with E[X]=1E[X]=1E[X]=1, E[X2]=0E[X^2]=0E[X2]=0, and E[X3]=2E[X^3]=2E[X3]=2. Define Y=−1+X+3X2Y=-1+X+3X^2Y=−1+X+3X2. Find Cov(X,Y)\operatorname{Cov}(X,Y)Cov(X,Y).Your answerPress Enter to check.
