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Question 13 - Week 3 Practice | Prasnya
Q13
00:00
4 Aug 2024
Q13.
Consider a random variable
X
X
X
with
E
[
X
]
=
1
E[X]=1
E
[
X
]
=
1
,
E
[
X
2
]
=
0
E[X^2]=0
E
[
X
2
]
=
0
, and
E
[
X
3
]
=
2
E[X^3]=2
E
[
X
3
]
=
2
. Define
Y
=
−
1
+
X
+
3
X
2
Y=-1+X+3X^2
Y
=
−
1
+
X
+
3
X
2
. Find
Cov
(
X
,
Y
)
\operatorname{Cov}(X,Y)
Cov
(
X
,
Y
)
.
Your Answer
Save
Check
Details
Q13
00:00
4 Aug 2024
Q13.
Consider a random variable
X
X
X
with
E
[
X
]
=
1
E[X]=1
E
[
X
]
=
1
,
E
[
X
2
]
=
0
E[X^2]=0
E
[
X
2
]
=
0
, and
E
[
X
3
]
=
2
E[X^3]=2
E
[
X
3
]
=
2
. Define
Y
=
−
1
+
X
+
3
X
2
Y=-1+X+3X^2
Y
=
−
1
+
X
+
3
X
2
. Find
Cov
(
X
,
Y
)
\operatorname{Cov}(X,Y)
Cov
(
X
,
Y
)
.
Your Answer
Save
Check
Details
