Q4Single correct3 Marks3 Aug 2025If X∼Normal(1,16)X \sim \mathrm{Normal}(1,16)X∼Normal(1,16) and Z=(X−1)/4Z=(X-1)/4Z=(X−1)/4, then find P(X2>16)P(X^2>16)P(X2>16).A1−[FZ(−5/4)−FZ(3/4)]1-[F_Z(-5/4)-F_Z(3/4)]1−[FZ(−5/4)−FZ(3/4)]BFZ(−5/4)−FZ(3/4)F_Z(-5/4)-F_Z(3/4)FZ(−5/4)−FZ(3/4)CFZ(3/4)−FZ(−5/4)F_Z(3/4)-F_Z(-5/4)FZ(3/4)−FZ(−5/4)D1−[FZ(3/4)−FZ(−5/4)]1-[F_Z(3/4)-F_Z(-5/4)]1−[FZ(3/4)−FZ(−5/4)]
