Q9Single correct3 Marks1 Dec 2024If X∼Exp(λ)X\sim\mathrm{Exp}(\lambda)X∼Exp(λ), find the PDF of Y=X2Y=X^2Y=X2.AfY(y)=λe−λy2, y>0; 0 otherwisef_Y(y)=\lambda e^{-\lambda y^2},\ y>0;\ 0\text{ otherwise}fY(y)=λe−λy2, y>0; 0 otherwiseBfY(y)=λ2ye−λy, y>0; 0 otherwisef_Y(y)=\frac{\lambda}{2\sqrt y}e^{-\lambda\sqrt y},\ y>0;\ 0\text{ otherwise}fY(y)=2yλe−λy, y>0; 0 otherwiseCfY(y)=λye−λy, y>0; 0 otherwisef_Y(y)=\lambda\sqrt y e^{-\lambda\sqrt y},\ y>0;\ 0\text{ otherwise}fY(y)=λye−λy, y>0; 0 otherwiseDfY(y)=λye−λy, y>0; 0 otherwisef_Y(y)=\frac{\lambda}{\sqrt y}e^{-\lambda\sqrt y},\ y>0;\ 0\text{ otherwise}fY(y)=yλe−λy, y>0; 0 otherwise
