Q15Single correct3 Marks3 Dec 2024Let XXX be a continuous random variable with PDF fX(x)=4x3f_X(x)=4x^3fX(x)=4x3 for 0<x≤10<x\le 10<x≤1, and 000 otherwise. Find the PDF of Y=X3Y=X^3Y=X3.AfY(y)=13y−2/3f_Y(y)=\frac{1}{3}y^{-2/3}fY(y)=31y−2/3, 0<y≤10<y\le 10<y≤1; 000 otherwiseBfY(y)=43y1/3f_Y(y)=\frac{4}{3}y^{1/3}fY(y)=34y1/3, 0<y≤10<y\le 10<y≤1; 000 otherwiseCfY(y)=13y2/3f_Y(y)=\frac{1}{3}y^{2/3}fY(y)=31y2/3, 0<y≤10<y\le 10<y≤1; 000 otherwiseDfY(y)=4y11f_Y(y)=4y^{11}fY(y)=4y11, 0<y≤10<y\le 10<y≤1; 000 otherwise
