Consider the procedure given below. If `L1` and `L2` are two lists, and `L = eliminate(L1, L2)`, choose the correct option regarding `L`.
```
Procedure eliminate(L1, L2)
L3 = [], Found = False
foreach i in L1 {
foreach j in L2 {
if (i == j) {
Found = True
}
}
if (not Found) {
L3 = L3 ++ [i]
}
Found = False
}
return(L3)
End eliminate
```