Question 15 - Week 6 Practice | Prasnya
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Week 6
Question 15
00:00
Est. 3 min
Marks:
+5.00
0.00
If
n
n
is the number of solutions of the equation
2
2
x
−
5
−
6
⋅
2
x
+
1
=
0
2^{2x-5}-6\cdot2^x+1=0
, then find the value of
4
n
4n
.
Integer answer
Medium Difficulty
06 August 2023
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