Question 5 - Week 7 Practice | Prasnya
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Week 7
Question 5
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+3.00
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Let
{
a
n
}
\{a_n\}
be a sequence defined as
a
n
=
27
n
4
+
25
n
3
+
2
n
5
+
n
4
n
2
+
2
n
+
10
n
3
+
5
n
5
+
n
a_n=\frac{27n^4+25n^3+2n^5+n}{4n^2+2n+10n^3+5n^5+n}
. Consider a sequence
{
b
n
}
\{b_n\}
defined as
b
n
=
2
5
a
n
b_n=2^{5a_n}
. Find the limit of
{
b
n
}
\{b_n\}
.
Integer answer
Medium Difficulty
03 August 2025
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