Question 42 - Week 7 Practice | Prasnya
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Week 7
Question 42
00:00
Est. 2 min
Marks:
+3.00
0.00
Consider a function
f
(
x
)
=
{
m
x
2
−
n
,
x
<
1
2
,
x
=
1
x
+
n
,
x
>
1.
f(x)=\begin{cases}mx^2-n,&x<1\\2,&x=1\\x+n,&x>1.\end{cases}
If
f
f
is continuous at
x
=
1
x=1
, then find the value of
m
+
n
m+n
.
Integer answer
EASY Difficulty
20 November 2022
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