Passage question

00:00Est. 2 min

Marks+2.000.00

Passage

Soumya considered

L=U

and Sohini considered

L'=(2,0,1)+U'

, where

U=\operatorname{span}\{(2,0,1),(1,1,0),(0,1,0)\}

and

U'=\operatorname{span}\{(1,0,1),(0,1,1)\}

. A linear transformation

T:U\to U'

satisfies

(0,1,0)\in\ker(T)

,

T(2,0,1)=(0,1,1)

, and

T(1,1,0)=(1,0,1)

. Define

f(u)=(2,0,1)+T(u)

.

Question

Which affine subspace was considered by Soumya?

ComprehensionMedium Difficulty20 November 2022