PassageBased on the above data, answer the given subquestions. Let X1,X2,…,XnX_1,X_2,\ldots,X_n be i.i.d. Exp(1/3)\mathrm{Exp}(1/3) and Xˉ=X1+X2+⋯+Xnn\bar{X}=\frac{X_1+X_2+\cdots+X_n}{n}.
QuestionFind the minimum value of nn such that the sample mean lies in [2.5,3.5][2.5,3.5] with probability more than 0.950.95 using Chebyshev inequality.