QuestionLet X1,X2,…,XnX_1,X_2,\ldots,X_n be i.i.d. XX with mean μ=0\mu=0 and variance σ2=1\sigma^2=1. Using Chebyshev's inequality, what should be the minimum value of nn such that the probability that the sample mean X1+X2+⋯+Xnn\frac{X_1+X_2+\cdots+X_n}{n} lies between −0.5-0.5 and 0.50.5 is at least 0.950.95?