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Question 77 - Algebra Practice | Prasnya
Q77
00:00
30 Nov 2025
Q77.
A value of c for which the minimum value of
f
(
x
)
=
x
2
−
4
c
x
+
8
c
f(x) = x^2 - 4cx + 8c
f
(
x
)
=
x
2
−
4
c
x
+
8
c
is greater than the maximum value of
g
(
x
)
=
−
x
2
+
3
c
x
−
2
c
g(x) = -x^2 + 3cx - 2c
g
(
x
)
=
−
x
2
+
3
c
x
−
2
c
, is
A
-2
B
−
1
2
-\frac12
−
2
1
C
2
D
1
2
\frac12
2
1
Save
Check
Details
Q77
00:00
30 Nov 2025
Q77.
A value of c for which the minimum value of
f
(
x
)
=
x
2
−
4
c
x
+
8
c
f(x) = x^2 - 4cx + 8c
f
(
x
)
=
x
2
−
4
c
x
+
8
c
is greater than the maximum value of
g
(
x
)
=
−
x
2
+
3
c
x
−
2
c
g(x) = -x^2 + 3cx - 2c
g
(
x
)
=
−
x
2
+
3
c
x
−
2
c
, is
A
-2
B
−
1
2
-\frac12
−
2
1
C
2
D
1
2
\frac12
2
1
Save
Check
Details
